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Compare version code use java.

16 Dec 2016 » java, codefights

Compare version code like 1.7.17.1, 1.12.17.1。

Solution: compare method

public class VersionUtil {

    /**
     * 比较版本号的大小,前者大则返回一个正数,后者大返回一个负数,相等则返回0
     * @param version1
     * @param version2
     * @return
     */
    public static int compareVersion(String version1, String version2) {
        String[] versionArray1 = version1.split("\\.");//注意此处为正则匹配,不能用".";
        String[] versionArray2 = version2.split("\\.");
        int idx = 0;
        int minLength = Math.min(versionArray1.length, versionArray2.length);//取最小长度值
        int diff = 0;
        while (idx < minLength
                && (diff = versionArray1[idx].length() - versionArray2[idx].length()) == 0//先比较长度
                && (diff = versionArray1[idx].compareTo(versionArray2[idx])) == 0) {//再比较字符
            ++idx;
        }
        //如果已经分出大小,则直接返回,如果未分出大小,则再比较位数,有子版本的为大;
        diff = (diff != 0) ? diff : versionArray1.length - versionArray2.length;
        return diff;
    }
}

Example:

  • how to use?
    VersionUtil.compareVersion("1.7.17.1", "1.12.17.1");

Done.